Python: How to get the first found element in a list or None • Programmer

To get the first element found in a list by some condition or None if nothing was found we can use the following construction:

elements_list = ['One', 'Two', 'Three']
element = next(iter([e for e in elements_list if e in ['One', 'Two']]), None)
print(element)
# 'One'

elements_list = ['One', 'Two', 'Three']

element = next(iter([e for e in elements_list if e in ['One', 'Two']]), None)

print(element)

# 'One'

With nothing found it returns None:

element = next(iter([e for e in elements_list if e in ['Four', 'Five']]), None)
print(element)
# None

element = next(iter([e for e in elements_list if e in ['Four', 'Five']]), None)

print(element)

# None